Two resistors, 100 Ω and 200 Ω, are connected in series to a 9 V battery. What is the total resistance and the current?

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Multiple Choice

Two resistors, 100 Ω and 200 Ω, are connected in series to a 9 V battery. What is the total resistance and the current?

In a series circuit, the resistances add together and the same current flows through each component. So the two resistors give a total resistance of 100 Ω + 200 Ω = 300 Ω. With a 9 V battery, the current is I = V / R = 9 V / 300 Ω = 0.03 A (30 mA). Therefore, the total resistance is 300 Ω and the current is 0.03 A.

In a series circuit, the resistances add together and the same current flows through each component. So the two resistors give a total resistance of 100 Ω + 200 Ω = 300 Ω. With a 9 V battery, the current is I = V / R = 9 V / 300 Ω = 0.03 A (30 mA). Therefore, the total resistance is 300 Ω and the current is 0.03 A.

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