In the same series circuit, what is the voltage across the 100 Ω resistor?

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Multiple Choice

In the same series circuit, what is the voltage across the 100 Ω resistor?

In a series circuit, the same current flows through every component, and the voltage across each resistor is proportional to its resistance (V = I × R). If the supply is 9 V and the resistors are 100 Ω and 200 Ω in series, the total resistance is 300 Ω, so the current is 9 V / 300 Ω = 0.03 A. The voltage across the 100 Ω resistor is V = I × R = 0.03 A × 100 Ω = 3 V. The remaining voltage (9 V − 3 V = 6 V) drops across the 200 Ω resistor, which checks out. Therefore, the voltage across the 100 Ω resistor is 3.0 V.

In a series circuit, the same current flows through every component, and the voltage across each resistor is proportional to its resistance (V = I × R). If the supply is 9 V and the resistors are 100 Ω and 200 Ω in series, the total resistance is 300 Ω, so the current is 9 V / 300 Ω = 0.03 A. The voltage across the 100 Ω resistor is V = I × R = 0.03 A × 100 Ω = 3 V. The remaining voltage (9 V − 3 V = 6 V) drops across the 200 Ω resistor, which checks out. Therefore, the voltage across the 100 Ω resistor is 3.0 V.

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