Get ready for the NCEA Level 1 Energy Test. Utilize flashcards and multiple choice questions with clear explanations and hints. Prepare for success!

Multiple Choice

In the same circuit, what is the voltage across the 200 Ω resistor?

In a series circuit, the same current flows through every component, and the voltages divide in proportion to the resistances. Here the two resistors add up to 300 Ω in total. If the supply is 9 V, the current is 9 V ÷ 300 Ω = 0.03 A. The voltage across the 200 Ω resistor is then V = I × R = 0.03 A × 200 Ω = 6 V. Since the 200 Ω resistor is larger, it takes a bigger share of the voltage, leaving 3 V for the 100 Ω resistor, and these two drops add to the 9 V supply.That's why the voltage across the 200 Ω resistor is 6 V.

In a series circuit, the same current flows through every component, and the voltages divide in proportion to the resistances. Here the two resistors add up to 300 Ω in total. If the supply is 9 V, the current is 9 V ÷ 300 Ω = 0.03 A. The voltage across the 200 Ω resistor is then V = I × R = 0.03 A × 200 Ω = 6 V. Since the 200 Ω resistor is larger, it takes a bigger share of the voltage, leaving 3 V for the 100 Ω resistor, and these two drops add to the 9 V supply.That's why the voltage across the 200 Ω resistor is 6 V.