In a series circuit with two resistors 5 Ω and 10 Ω connected to a 12 V supply, what is the current? And what is voltage across each resistor?

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Multiple Choice

In a series circuit with two resistors 5 Ω and 10 Ω connected to a 12 V supply, what is the current? And what is voltage across each resistor?

In a series circuit, the same current flows through every component, and you find that current from the supply voltage divided by the total resistance. The two resistors add to a total of 15 Ω, so the current is 12 V / 15 Ω = 0.8 A. The voltage across each resistor is V = I × R. For the 5 Ω resistor: 0.8 A × 5 Ω = 4 V. For the 10 Ω resistor: 0.8 A × 10 Ω = 8 V. These voltages add up to the 12 V supply (4 V + 8 V). Therefore, the current is 0.8 A, with 4 V across the 5 Ω resistor and 8 V across the 10 Ω resistor.

In a series circuit, the same current flows through every component, and you find that current from the supply voltage divided by the total resistance. The two resistors add to a total of 15 Ω, so the current is 12 V / 15 Ω = 0.8 A. The voltage across each resistor is V = I × R. For the 5 Ω resistor: 0.8 A × 5 Ω = 4 V. For the 10 Ω resistor: 0.8 A × 10 Ω = 8 V. These voltages add up to the 12 V supply (4 V + 8 V). Therefore, the current is 0.8 A, with 4 V across the 5 Ω resistor and 8 V across the 10 Ω resistor.

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