A 3.0 N force moves an object 2.0 m in the direction of the force. How much work is done?

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Multiple Choice

A 3.0 N force moves an object 2.0 m in the direction of the force. How much work is done?

Work is the energy transferred when a force moves an object along a distance, and it’s calculated with W = F d cos(theta). Here the force of 3.0 N acts in the same direction as the motion, so theta is 0 degrees and cos(0) = 1. The full force contributes to the work, giving W = 3.0 N × 2.0 m × 1 = 6.0 joules. So the work done is 6 joules. If the force were at an angle to the motion, only the component along the displacement would do work (F cos theta times d), which would yield a smaller value.

Work is the energy transferred when a force moves an object along a distance, and it’s calculated with W = F d cos(theta). Here the force of 3.0 N acts in the same direction as the motion, so theta is 0 degrees and cos(0) = 1. The full force contributes to the work, giving W = 3.0 N × 2.0 m × 1 = 6.0 joules. So the work done is 6 joules. If the force were at an angle to the motion, only the component along the displacement would do work (F cos theta times d), which would yield a smaller value.

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