A 0.25 kg metal spoon has c = 500 J/kg°C. If it is heated by 20°C, how much energy is absorbed?

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Multiple Choice

A 0.25 kg metal spoon has c = 500 J/kg°C. If it is heated by 20°C, how much energy is absorbed?

The energy absorbed when raising the temperature is found using q = m c ΔT. Here m = 0.25 kg, c = 500 J/(kg·°C), and ΔT = 20°C. Compute step by step: 0.25 × 500 = 125 J/°C. Then 125 × 20 = 2,500 J. So the spoon absorbs 2,500 joules (2.5 kJ) of energy.

The energy absorbed when raising the temperature is found using q = m c ΔT. Here m = 0.25 kg, c = 500 J/(kg·°C), and ΔT = 20°C.

Compute step by step: 0.25 × 500 = 125 J/°C. Then 125 × 20 = 2,500 J.

So the spoon absorbs 2,500 joules (2.5 kJ) of energy.

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